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UP TGT Science 2019 Official Paper

Option 2 : -6000 m/s2

CT 1: हिन्दी (आदिकाल)

6220

10 Questions
40 Marks
10 Mins

__Concept__:

- Acceleration: The time rate of change of velocity of an object is called the acceleration of the object.

\(a = \frac{{{v_2} - {v_1}}}{{{t_2} - {t_1}}}\)

Where v2 = velocity of the object at t2 and v1 = velocity of the object at t1

- It is a vector quantity.
- It’s direction is the same as that of change in velocity (Not of the velocity).

**Calculation:**

Initial velocity (v_{1}) = 25 m/s

Final velocity (v_{2}) = - 35 m/s (opposite direction)

Time taken = 0.010 sec

We know that,

\(a = \frac{{{v_2} - {v_1}}}{{{t_2} - {t_1}}}\)

\(\Rightarrow a = \frac{{{-35} - {25}}}{{0.010}}=- {60\over{0.01}}=-{6000} \; m/s^2\)

__ Hence the acceleration is - 6000 m/s__2